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Fortunately, in the discussion of queuing, WFQ and CBWFQ are probably the two most detailed and complex of the queuing methods However, they are also the most forgiving and dynamic of the queuing methods, and typically the most useful Custom queuing (CQ), on the other hand, is fairly simple It classifies traffic similarly to CBWFQ, placing the traffic into one of 17 queues However, CQ statically defines the bandwidth and queuing logic, making it able to more specifically define bandwidth use, but also reducing its flexibility to transient traffic needs To illustrate this concept, let's look at how CQ works First, you must assign traffic to queues You perform this task similarly to how you do it when using CBWFQ by using packet details such as IP addresses (source and destination), protocol types, port numbers, and so on In this classification process, you choose which queue to place each type of traffic in, using queues 1 through 16 (Queue 0 is reserved by the system for signaling packets, keepalives, and other system necessities) For each queue, you specify a byte count These byte counts specify the amount of traffic that will be sent from each queue before moving on to the next queue CQ goes in order, from Queue 0 to Queue 16, sending all packets in each queue until it reaches the byte count threshold for the queue, or when all packets in the queue have been delivered By specifying which types of traffic go into which queues, and the byte count limits on each queue, you can specify the priority of traffic (for low-latency applications) and the total amount of bandwidth each traffic type will use Finally, you specify the packet limit for each queue When a queue reaches its configured packet limit, it discards any further packets attempting to enter that particular queue Configuring the packet limit allows you to ensure that queues do not stay perpetually full The real trick to CQ is setting the byte limits By using the byte limits properly, you can specify the specific amount of bandwidth allocated to a particular class of traffic For instance, if your total outgoing bandwidth is 768 Kbps, that is the figure by which you divide your bandwidth You then figure out how many traffic classes you need and what the bandwidth requirements are for each class of traffic If class 1 traffic requires 25 percent of the bandwidth, class 2 requires 10 percent, and all other traffic should get the remaining bandwidth, you have a basic calculation In this case, 192 Kbps should go to class 1, 77 Kbps should go to class 2, and 499 Kbps to all other traffic. asp.net code 39 barcode C# Imaging - C# Code 39 Barcoding Tutorial - RasterEdge.com
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Creator.dll for C# developers to generate and create Code 39 on TIFF, PDF, Word, Excel and ... NET Tiff Viewer: view, annotate multipage Tiff images in ASP . However, configuring CQ is not as simple as setting a 192,000-byte limit on Queue 1, a 77,000-byte limit on Queue 2, and a 499,000-byte limit on Queue 3 If you did that, the latency would be a bit high because each queue is processed in order, and CQ will not switch from one queue to another until either all bytes up to the byte limit have been transferred or the queue is empty For instance, if Queue 2 and Queue 3 were full, Queue 1 would have to wait at least 750 milliseconds (075 seconds) to be serviced an eternity in computer terms To put that time in perspective, right now, over a modem connection, a ping to yahoocom takes me approximately 150 ms That means, through 12 routers, it took less than 75 ms for my packet to reach the server and less than 75 ms for it to return Obviously, a 750-ms wait (just on the sending side; once you count the return packet, it becomes a 15-second wait) is unacceptable Tip The following example contains my own calculations for figuring out how to set byte limits in CQ Although I think this way works better for understanding what you are doing, Cisco actually has a quicker method to perform the same task, which is detailed at the following web address: http://wwwciscocom/ univercd/cc/td/doc/ product/software/ios121/ 121cgcr/qos_c/qcprt2/ qcdconmghtm#xtocid840033 A better way to set byte limits is to chop the total bandwidth into smaller time slices and use those to determine the byte limits For instance, if you chopped the bandwidth up into 1/40th of a second, Queue 1 would get a byte limit of 4800 (384,000 divided by 40 equals 4800), Queue 2 would get 1925 (77,000 divided by 40), and Queue 3 would get 12,475 (499,000 divided by 40) This arrangement would give Queue 1 a wait time of about 19 ms if both Queues 2 and 3 were full This scenario is much better, but in reality, it should probably be even lower The problem with setting the queue significantly lower than this is that, even though you set the limit in bytes, the router can send only full packets So, if your packet sizes were always 1500 bytes (the maximum size for Ethernet), when Queue 2 is processed, it will actually send 3000 bytes instead of 1925 Applying the same logic to Queue 1 and Queue 3, you end up with 6000 bytes for Queue 1 and 13,500 bytes for Queue 3, giving you a bandwidth split of 266 percent for Queue 1, 133 percent for Queue 2, and 60 percent for Queue 3, which isn't exactly desirable So, to correctly set the byte limits, you need to take a look at what the average packet size is for each queue Say, for instance, that the application used for Queue 1 has an average packet size of 1000 bytes, Queue 2 has an average packet size of 1200 bytes, and Queue 3 has an average packet size of 800 bytes Well, to figure the correct ratio out, you need to figure out what the ratio of packets is for each queue In other words, how many packets do you want sent out of Queue 1, as compared to packets from Queue 2 and Queue 3 Well, based on the bandwidth breakdown, you want 192,000 bytes allocated for Queue 1, which is 192 packets You want 77,000 bytes from Queue 2, which is about 64 packets (641, rounded down so that the result is even), and 499,000 bytes from Queue 3, which is about 624 packets (6237, rounded up so that the result is even) Tip For this calculation to work, the packet numbers must be even Now you need to figure out what the byte size is if you divide the second interval into the smallest possible pieces, and the easiest strategy is to find the highest common denominator (HCD) for all of the packet results (Break out the calculator!) In this case, the HCD for these. asp.net code 39 Code39 Barcodes in VB. NET and C# - CodeProject
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